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3n^2-88=10n
We move all terms to the left:
3n^2-88-(10n)=0
a = 3; b = -10; c = -88;
Δ = b2-4ac
Δ = -102-4·3·(-88)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-34}{2*3}=\frac{-24}{6} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+34}{2*3}=\frac{44}{6} =7+1/3 $
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